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scipy.signal.

# freqs

scipy.signal.freqs(b, a, worN=200, plot=None)

  Compute frequency response of analog filter.

  Given the M-order numerator b and N-order denominator a of an analog filter, compute its frequency response:

              b[0]*(jw)**M + b[1]*(jw)**(M-1) + ... + b[M]
      H(w) = ----------------------------------------------
              a[0]*(jw)**N + a[1]*(jw)**(N-1) + ... + a[N]

  Parameters:
    barray_like

      Numerator of a linear filter.

    aarray_like

      Denominator of a linear filter.

    worN{None, int, array_like}, optional

      If None, then compute at 200 frequencies around the interesting parts of the response curve (determined by pole-zero locations). If a single integer, then compute at that many frequencies. Otherwise, compute the response at the angular frequencies (e.g., rad/s) given in worN.

    plotcallable, optional

      A callable that takes two arguments. If given, the return parameters w and h are passed to plot. Useful for plotting the frequency response inside `freqs`.

  Returns:
    wndarray

      The angular frequencies at which h was computed.

    hndarray

      The frequency response.

  See also

  `freqz`

    Compute the frequency response of a digital filter.

  Notes

  Using Matplotlib’s “plot” function as the callable for plot produces unexpected results, this plots the real part of the complex transfer function, not the magnitude. Try `lambda w, h: plot(w, abs(h))`.

  Examples

      >>> from scipy.signal import freqs, iirfilter
      >>> import numpy as np

      >>> b, a = iirfilter(4, [1, 10], 1, 60, analog=True, ftype='cheby1')

      >>> w, h = freqs(b, a, worN=np.logspace(-1, 2, 1000))

      >>> import matplotlib.pyplot as plt
      >>> plt.semilogx(w, 20 * np.log10(abs(h)))
      >>> plt.xlabel('Frequency [rad/s]')
      >>> plt.ylabel('Amplitude response [dB]')
      >>> plt.grid(True)
      >>> plt.show()