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scipy.linalg.

# hilbert

scipy.linalg.hilbert(n)

  Create a Hilbert matrix of order n.

  Returns the n by n array with entries h[i,j] = 1 / (i + j + 1).

  Parameters:
    nint

      The size of the array to create.

  Returns:
    h(n, n) ndarray

      The Hilbert matrix.

  See also

  `invhilbert`

    Compute the inverse of a Hilbert matrix.

  Notes

  Added in version 0.10.0.

  Examples

      >>> from scipy.linalg import hilbert
      >>> hilbert(3)
      array([[ 1.        ,  0.5       ,  0.33333333],
             [ 0.5       ,  0.33333333,  0.25      ],
             [ 0.33333333,  0.25      ,  0.2       ]])